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A fringe width of 6 mm was produced ....

A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is 'x' nm. The value of 'x' to the nearest integer is _ _ _ _ .

Solution

Fringe width = 6mm=λDd=λ×101×103

λ=6×103×10310=6×107=600nm

x=600

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