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Let I=π/20dx1+tantanαx

dIdα=?

We have, I=π/20dx1+tantanα(π/2x)

I=π/20dx1+cottanαx=π/20sintanαx.dxsintanαx+costanαx ........(A)

Also, I=π/20dx1+tantanαx=π/20costanαx.dxcostanαx+sintanαx ........(B)

(A) + (B) gives, 2I=π/20dx=π2

I=π4

dIdα=0

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